\(\Leftrightarrow\left(x+1\right)\left(4x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-1\\x=\dfrac{1}{4}\end{matrix}\right.\)
Vậy có 2 giá trị x
\(4x\left(x+1\right)=x+1\Rightarrow4x\left(x+1\right)-\left(x+1\right)=0\)
\(\Rightarrow\left(4x-1\right)\left(x+1\right)=0\)\(\Rightarrow\left[{}\begin{matrix}4x-1=0\\x+1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=-1\end{matrix}\right.\)
Vậy có 2 giá trị x.