\(\dfrac{x-2}{4}=\dfrac{-1-x}{-7}\)
\(\dfrac{-7\left(x-2\right)}{-28}=\dfrac{4\left(-1-x\right)}{-28}\)
\(-7\left(x-2\right)=4\left(-1-x\right)\)
\(-7x+14=-4-4x\)
\(-7x+4x=-4-14\)
\(-3x=-18\)
\(x=\dfrac{-18}{-3}\)
\(x=6\)
\(\left(x-1\right)-7=4\left(-1-x\right)\\ -7x+7=-4-4x\\ -7x-7+4+4x=0\\ -3x-3=0\\ -3\left(x-1\right)=0\\ x-1=0\\ x=1\)