`(x- 2)(x^2 + 2x + 4) + 2(x^2 - 4) - 5x(x - 2) = 0`
`(x - 2)(x^2 + 2x + 4) + 2(x - 2)(x + 2) - 5x(x - 2) = 0`
`(x - 2)[x^2 + 2x + 4 + 2(x + 2) - 5x] = 0`
`(x - 2)(x^2 + 2x + 4 + 2x + 4 - 5x) = 0`
`(x - 2)(x^2 - x + 8) = 0`
`x - 2 = 0 (` Mà `x^2 - x + 8 \ne 0)`
`x = 0 + 2`
`x = 2`
Vậy: `x=2`
(x−2)(x2+2x+4)+2(x2 −4)−5x(x−2)=0(x-2)(x2+2x+4)+2(x2 -4)-5x(x-2)=0
(x−2)(x2+2x+4)+2(x−2)(x+2)−5x(x−2)=0(x-2)(x2+2x+4)+2(x-2)(x+2)-5x(x-2)=0
(x−2)[x2+2x+4+2(x+2)−5x]=0(x-2)[x2+2x+4+2(x+2)-5x]=0
(x−2)(x2+2x+4+2x+4−5x)=0
Vậy x ta tìm được=2 (x2 là x mũ 2,tui ko viết được số mũ)
