Question

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Answer 1

ĐKXĐ: x<>1 và y<>0

\(\left\{{}\begin{matrix}\dfrac{1}{x-1}+\dfrac{1}{y}=-1\\\dfrac{3}{x-1}-\dfrac{2}{y}=7\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}\dfrac{2}{x-1}+\dfrac{2}{y}=-2\\\dfrac{3}{x-1}-\dfrac{2}{y}=7\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{5}{x-1}=5\\\dfrac{1}{x-1}+\dfrac{1}{y}=-1\end{matrix}\right.\)

=>\(\left\{{}\begin{matrix}x-1=1\\\dfrac{1}{y}=-1-1=-2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=-\dfrac{1}{2}\end{matrix}\right.\left(nhận\right)\)