\(VT:25^6\cdot8^8=\left(5^2\right)^6\cdot\left(2^3\right)^8\)
\(=5^{12}\cdot2^{32}\)
\(=5^{12}\cdot\left(2^2\right)^{12}\)
\(=5^{12}\cdot4^{12}\)
\(=\left(5\cdot4\right)^{12}\)
\(=20^{12}=VP\)
\(\Rightarrowđpcm\)
Ta có \(25^6=\left(5^2\right)^6=5^{16}\)
\(8^8=\left(2^3\right)^8=2^{36}=\left(2^2\right)^{12}\)
<=> \(5^{12}.4^{12}=\left(5.4\right)^{12}=20^{12}\)
Good Luck To You