Question

Cho:

\(\frac{7-3x}{5}=\frac{y+4}{3}=\frac{6x-y}{5}\).  Tìm tỉ số y và x

Answer 1

\(\Leftrightarrow\frac{7-3x}{5}=\frac{y+4}{3}=\frac{6x-y}{5}\)

\(\Rightarrow\frac{-3x-7}{5}=\frac{y+4}{3}\)

\(\Rightarrow\frac{-y+4}{3}-\frac{3x-7}{5}=0\)

\(\Leftrightarrow\frac{-5y+9x-1}{15}=0\)<=>5y+9x-1=0

\(\Rightarrow\frac{y+4}{3}=\frac{-y-6x}{5}\)

\(\Rightarrow\frac{y+4}{3}-\left(\frac{-y-6x}{5}\right)=0\)

\(\Leftrightarrow\frac{2\left(4y-9x+10\right)}{15}=0\)

=>2(4y-9x+10)=0

=>4y-9x+10=0

=>x=\(\frac{2}{3}\);y=-1