C2H2+2Br2->C2H2Br4
0,05-----0,1
n Br2=\(\dfrac{16}{160}\)=0,1 mol
=>VC2H2=0,05.22,4=1,12l
CaC2+2H2O->Ca(OH)2+C2H2
0,05------------------------------0,05
=>m CaC2=0,05.64=3,2g
\(n_{Br_2}=\dfrac{16}{160}=0,1mol\)
\(C_2H_2+2Br_2\rightarrow C_2H_2Br_4\)
0,05 0,1 ( mol )
\(V_{C_2H_2}=0,05.22,4=1,12l\)
\(CaC_2+2H_2O\rightarrow C_2H_2+Ca\left(OH\right)_2\)
0,05 0,05 ( mol )
\(m_{CaC_2}=0,05.64=3,2g\)