Ta có: \(\frac{a}{b}=\frac{a+c}{b+d}\)
\(\Leftrightarrow a\left(b+d\right)=b\left(a+c\right)\\ \Leftrightarrow ab+ad=ab+bc\\ \Leftrightarrow ad=bc\Leftrightarrow\frac{a}{b}=\frac{c}{d}\)
=> ĐPCM.
ta có: \(\frac{a}{b}=\frac{a+c}{b+d}\) \(\Rightarrow a\left(b+d\right)=b\left(a+c\right)\)
\(\Leftrightarrow ab+ad=ba+bc\)
\(\Leftrightarrow ad=bc\Leftrightarrow\frac{a}{b}=\frac{c}{d}\)
Vậy \(\frac{a}{b}=\frac{a+c}{b+d}\) \(\Leftrightarrow\frac{a}{b}=\frac{c}{d}\)
Ta có: \(\frac{a}{b}=\frac{a+c}{b+d}.\)
\(\Rightarrow a.\left(b+d\right)=b.\left(a+c\right)\)
\(\Rightarrow ab+ad=ab+bc\)
\(\Rightarrow ad=bc\)
\(\Rightarrow\frac{a}{b}=\frac{c}{d}\left(đpcm\right).\)
Chúc bạn học tốt!