a: Xét ΔCDH va ΔBAH có
góc DCH=góc ABH
góc CHD=góc AHB
=>ΔCDH đồng dạng với ΔBAH
=>DH/AH=DC/AB=HC/HB
AC^2=HC*HB; AB^2=BC*BH
AC^2=AH*AD; CD^2=DH*DA
CH/HB=DC/AB=DC*AB/AB^2
=>HC/HB*AB^2=DC*AB
=>CH*BC=AH*AD=AB*DC
c: cos^3B=BE/HB*HB/AB*BA/BC=BE/BC
=>BE=BC*cos^3B
d: HE//AB
=>HE/AC=BH/BC=AB^2/BC^2
=>EH=AB^2*AC/BC
b: