Question

cho \(P=P=(x-4)\) \(^(\)\(^x\)\(^-\)\(^5\)\(^)\)\(^(\)\(^x\)\(^-\)\(^6\)\(^)\)\(^(\)\(^x\)\(^+\)\(^6\)\(^)\)\(^(\)\(^x\)\(^+\)\(^5\)\(^)\)

Tính \(P\) khi \(x=7\)

Answer 1

\(P_{\left(x\right)}=\left(x-4\right)^{\left(x-5\right)\left(x-6\right)\left(x+6\right)\left(x+5\right)}\\ P_{\left(x\right)}=\left(x-4\right)^{\left(x^2-25\right)\left(x^2-36\right)}\)

Thay `x = 7`

\(P_{\left(x\right)}=\left(7-4\right)^{\left(7^2-25\right)\left(7^2-36\right)}\\ =3^{24.13}\\ =3^{312}\)

Answer 2