tính giới hạn
a) \(\lim\limits_{x\rightarrow+\infty}\dfrac{x+1}{x^2+x+1}\)
b) \(\lim\limits_{x\rightarrow+\infty}\dfrac{3x+1}{3x^2-x+5}\)
c) \(\lim\limits_{x\rightarrow-\infty}\dfrac{3x+5}{\sqrt{x^2+x}}\)
d) \(\lim\limits_{x\rightarrow+\infty}\dfrac{-5x+1}{\sqrt{3x^2+1}}\)
4. Tính giới hạn \(\lim\limits_{x\rightarrow0}\dfrac{\sqrt{x^2+1}-x-1}{2x^2-x}_{ }\)
5. Tính giới hạn:
a) \(\lim\limits_{x\rightarrow2}\dfrac{x-2}{x^2-4}_{ }\)
b) \(\lim\limits_{x\rightarrow3^-}\dfrac{x+3}{x-3}_{ }\)
Cho f(x) là hàm đa thức thỏa \(\lim\limits_{x\rightarrow2}\dfrac{f\left(x\right)+1}{x-2}=a\left(a\in R\right)\) và tồn tại \(\lim\limits_{x\rightarrow2}\dfrac{\sqrt{f\left(x\right)+2x+1}-x}{x^2-4}=T\left(T\in R\right).\) Tìm T theo a.
1.lim(\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{n\left(n+1\right)}\))
2.Tìm tất cả các giá trị của a sao cho lim\(\frac{4^n+a.5^n}{\left(2a-1\right).5^n+2^n}\)=1
3. Cho \(a\in R\)và lim(\(\sqrt{n^2+an+4}-n+1=5\)).Tìm a
4.Cho\(Lim_{(x->2)}f\left(x\right)=5\). Tìm giới hạn \(lim_{\left(x->2\right)}\sqrt{[f\left(x\right)-3]x}\)
a) \(\lim\limits_{x\rightarrow+\infty}\)\(^{3_{\sqrt{x^3+4x^2}-x}}\)
b) \(f\left(x\right)=\left\{{}\begin{matrix}\dfrac{4x-1}{x-1}neux>1\\7x+1neux< 1\end{matrix}\right.\)
Tính \(\lim\limits f\left(x\right)_{x\rightarrow1^+}\) , \(\lim\limits f\left(x\right)_{x\rightarrow1^-}\)
tính giới hạn
a) \(\lim\limits_{x\rightarrow+\infty}\dfrac{5x^2+x^3+5}{4x^3+1}\)
b) \(\lim\limits_{x\rightarrow-\infty}\dfrac{2x^2-x+1}{x^3+x-2x^2}\)
c) \(\lim\limits_{x\rightarrow-\infty}\dfrac{2x^2-x+1}{x^3+x-2x^2}\)
a) \(\lim\limits_{x\rightarrow1}\dfrac{\sqrt{2x+2}+\sqrt{5x+4}-5}{x-1}_{ }\)
b) \(\lim\limits_{x\rightarrow0}\dfrac{\sqrt{4x+4}+\sqrt{90-6x}-5}{x^2}\)
e) lim\(\dfrac{17}{x^2+1}\)(x-->+\(\infty\))
f) lim\(\dfrac{-2x^2+x-1}{3+x}\)(x-->+\(\infty\))
Cho hàm số y = f x = a x 5 + b x 3 + c x + d a , b , c , d ∈ ℝ ; a ≠ 0 . Biết f'(-1)=3 . Tính lim ∆ x → 0 f 1 + ∆ x - f 1 ∆ x
A. 3
B. -3
C. 1
D. -1
1) \(\lim\limits_{x\rightarrow4}\dfrac{\sqrt{2x+1}-\sqrt{x+5}}{x-4}\)
2) \(\lim\limits_{x\rightarrow0}\dfrac{\sqrt{1-x}-\sqrt{1+x}}{x}\)