Ta có: \(n_{O_2}=\dfrac{8,96}{22,4}=0,4\left(mol\right)\)
\(n_{N_2}=\dfrac{x}{22,4}\left(mol\right)\)
Ta có: \(\overline{M_{hh}}=\dfrac{32.0,4+\dfrac{x}{22,4}.28}{0,4+\dfrac{x}{22,4}}\left(g\right)\)
=> \(\dfrac{\dfrac{32.0,4+\dfrac{x}{22,4}.28}{0,4+\dfrac{x}{22,4}}}{2}=15\left(lần\right)\)
=> \(x=8,96\left(lít\right)\)