\(\left|\overrightarrow{BC}+\overrightarrow{AB}\right|=\left|\overrightarrow{AC}\right|=AC=a\)
\(\left|\overrightarrow{AB}-\overrightarrow{AC}\right|=\left|\overrightarrow{AB}+\overrightarrow{CA}\right|=\left|\overrightarrow{CB}\right|=CB=a\)
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