Vì ABCD là hình thang
nên \(S_{AOD}=S_{BOC}=10\left(cm^2\right)\)
OA/OC=1/4
=>\(S_{AOB}=\dfrac{1}{4}\cdot S_{BOC}=\dfrac{1}{4}\cdot10=2.5\left(cm^2\right)\)
OC=4OD
=>\(S_{COD}=4\cdot S_{AOD}=40\left(cm^2\right)\)
=>\(S_{ABCD}=10+10+40+2.5=62.5\left(cm^2\right)\)