Vì MN // AC nên
\(\Rightarrow\frac{MA}{BA}=\frac{NC}{BC}\Rightarrow MA.BC=NC.BA\)
\(\Rightarrow MA.AD=NC.DC\)
\(\Rightarrow\frac{1}{2}.MA.AD.\sin\left(\widehat{MAD}\right)=\frac{1}{2}.NC.DC.\sin\left(\widehat{MAD}\right)\)
\(\Rightarrow\Rightarrow\frac{1}{2}.MA.AD.\sin\left(\widehat{MAD}\right)=\frac{1}{2}.NC.DC.\sin\left(\widehat{NCD}\right)\)
\(\Rightarrow S_{ADM}=S_{CDN}\)