\(\int f\left(x\right).e^xdx=cos2x+C\Rightarrow f\left(x\right).e^x=\left(cos2x+C\right)'=-2sin2x\)
\(I=\int f'\left(x\right).e^xdx\)
Đặt \(\left\{{}\begin{matrix}u=e^x\\dv=f'\left(x\right)dx\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}du=e^xdx\\v=f\left(x\right)\end{matrix}\right.\)
\(\Rightarrow I=e^x.f\left(x\right)-\int f\left(x\right).e^xdx=-2sin2x-cos2x+C\)