Cho \(\dfrac{bz+cy}{x\left(-ax+by+cz\right)}=\dfrac{cx+az}{y\left(ax-by+cz\right)}=\dfrac{ay+bx}{z\left(ax+by-cz\right)}\)
CMR : \(\dfrac{ay+bx}{c}=\dfrac{bz+cy}{a}=\dfrac{cx+az}{b}\)
b) \(\dfrac{x}{a\left(b^2+c^2-a^2\right)}=\dfrac{y}{b\left(a^2+c^2-b^2\right)}=\dfrac{z}{c\left(a^2+b^2-c^2\right)}\)
\(\dfrac{bz-cy}{a}=\dfrac{cx-az}{b}=\dfrac{ay-bx}{c}\left(a,b,c\ne0\right)\)
CMR: \(\dfrac{x}{a}=\dfrac{y}{b}=\dfrac{z}{c}\)
2) Cho a,b,c, d \(\in\) N*, b là trung bình cộng của a và c và \(\dfrac{1}{c}=\dfrac{1}{2}\left(\dfrac{1}{b}+\dfrac{1}{d}\right)\)
CMR: a,b,c,d lập nên 1 tỉ lệ thức
Bài 1: Cho 4 số a,b,c,d thỏa mãn \(b^2=ac;c^2=bd\\ \) . Chứng minh \(\dfrac{a}{d}=\left(\dfrac{a+b+c}{b+c+d}\right)^3\)
Bài 2 : Cho \(\dfrac{a}{b}=\dfrac{c}{d}\). Chứng minh
a) \(\dfrac{7a^2+3ab}{11a^2-8b^2}=\dfrac{7c^2+3cd}{11c^2-8d^2}\)
b) \(\dfrac{ab}{cd}=\dfrac{a^2-b^2}{c^2-d^2}\)
Bài 3 : CMR : Nếu a(y+z)=b(z+x)=c(x+y) trong đó a,b,c là các số thực khác nhau thì \(\dfrac{y-z}{a\left(b-c\right)}=\dfrac{z-x}{b\left(c-a\right)}=\dfrac{x-y}{c\left(a-b\right)}\)
Bài 4 : Cho \(\dfrac{bz-cy}{a}=\dfrac{cx-az}{b}=\dfrac{ay-bx}{c}\). Chứng minh \(\dfrac{x}{a}=\dfrac{y}{b}=\dfrac{z}{c}\)
Bài 5 : CMR : Nếu \(\dfrac{x}{a+2b+c}=\dfrac{y}{2a+b-c}=\dfrac{z}{4a-4b+c}\) thì \(\dfrac{a}{x+2y+z}=\dfrac{b}{2x+y-z}=\dfrac{c}{4x-4y+z}\)
Cho : \(\dfrac{cy-bz}{x}=\dfrac{az-cx}{y}=\dfrac{bx-ay}{z}.\) CMR : \(\dfrac{a}{x}=\dfrac{b}{y}=\dfrac{c}{z}\)
Tính giá trị biểu thức
\(A=\dfrac{\left(a+b\right)\left(-x-y\right)-\left(a-y\right)\left(b-c\right)}{abxy\left(xy+ay+ab+bx\right)}\) với \(a=-2;x=\dfrac{1}{3};b=\dfrac{2}{3};y=-1\)
Bài 1 : Cho \(\dfrac{U+2}{U-2}\) = \(\dfrac{V+3}{V-3}\) và \(U^2\) + \(V^2\) = 52 .
Tính U ; V .
Bài 2 : Cho \(\dfrac{x}{y}=\dfrac{z}{t}\) . Cmr \(\dfrac{x.y}{z.t}=\dfrac{\left(x+y\right)^2}{\left(z+t\right)^2}\) .
Bài 3 : Cho \(\dfrac{a}{a'}=\dfrac{b}{b'}=\dfrac{c}{c'}=\text{4}\) . Tính M \(\dfrac{a-3b+2c}{a'-3b'+2c'}\) .
Bài 4 : Cho \(\left(a_2\right)^2=a_1.a_3;\left(a_3\right)^2=a_2.a_4\) .
Cmr \(\dfrac{\left(a_1\right)^2+\left(a_2\right)^2+\left(a_3\right)^2}{\left(a_2\right)^2+\left(a_3\right)^2+\left(a_4\right)^2}=\dfrac{a_1}{a_3}\) .
Bài 5 : Cho \(\dfrac{a}{c}=\dfrac{c}{b}\) . Cmr :
a) \(\dfrac{a^2+c^2}{b^2+c^2}=\dfrac{a}{b}\)
b) \(\dfrac{b^2-a^2}{a^2+c^2}=\dfrac{b-c}{a}\)
cho a(y+z)=b(z+x)=c(x+y) chứng minh \(\dfrac{y-z}{a\left(b-c\right)}=\dfrac{z-x}{b\left(c-a\right)}=\dfrac{x-y}{c\left(a-b\right)}\)
Chứng minh nếu \(\dfrac{a}{b}\)= \(\dfrac{c}{d}\) thì:
\(\dfrac{a+c}{b+d}=\dfrac{a-c}{b-d}\)
Tìm
a. Min A = 3 \(\left|2x+1\right|\)-4
b. min B = \(\dfrac{3}{\left|x\right|-2}\)(x ϵ Z)
c. max A = \(\dfrac{1}{2\left(x-2\right)^2+2}\)
d. max B = \(\dfrac{x+1}{\left|x\right|}\left(x\in Z\right)\)
Tìm x, y, z:
a) \(\left|x+\dfrac{19}{5}\right|+\left|y+\dfrac{1890}{1975}\right|+\left|z-2005\right|=0\)
b) \(\left|x+\dfrac{3}{4}\right|+\left|y-\dfrac{1}{5}\right|+\left|x+y+z\right|\) = 0
c) \(\dfrac{16}{2^x}=1\)
d) \(\left(2x-1\right)^3=-27\)
e) \(\left(x-2\right)^2=1\)
f) \(\left(x+\dfrac{1}{2}\right)^2=\dfrac{4}{25}\)
g) \(\left(x-1\right)^2=\left(x-1\right)^6\)
Cho 3 số hữu tỉ dương a;b;c thỏa mãn: \(\dfrac{a+b-2c}{c}=\dfrac{b+c-2a}{a}=\dfrac{c+a-2b}{b}\)
Tính giá trị biểu thức: P = \(\left(1+\dfrac{a}{b}\right)\left(2+\dfrac{b^2}{c^2}\right)\left(3+\dfrac{c^3}{a^3}\right)\)
