Question

Cho ΔABC=ΔMNP. Góc C=70^o. Tính góc M + góc N

 

Answer 1

Ta có:
\(\Delta ABC=\Delta MNP\)
\(\Rightarrow\widehat{C}=\widehat{P}\) (hai góc tương ứng)
Mà \(\widehat{C}=70^o\) nên:
\(\widehat{P}=70^o\)
Xét \(\Delta MNP\) có:
\(\widehat{M}+\widehat{N}+\widehat{P}=180^o\) (Định lý)
Mà \(\widehat{P}=70^o\) nên:
\(\widehat{M}+\widehat{N}=180^o-70^o\\ \Rightarrow\widehat{M}+\widehat{N}=110^o\)
Vậy...

Answer 2

Do `ΔABC=ΔMNP`

`=> hat{C} = hat{P}` (2 góc tương ứng)

Mà `hat{C} = 70^o -> hat{P} = 70^o`

`ΔMNP có hat{M} + hat{N} + hat{P} = 180^o`

`=> hat{M} + hat{N} + 70^o = 180^o`

`=> hat{M} + hat{N} = 110^o`

Vậy ..