a: ĐKXĐ: x>0; x<>1
b: \(A=\left(\dfrac{1}{\sqrt{x}-1}+\dfrac{1}{\sqrt{x}+1}\right)\cdot\dfrac{\sqrt{x}+1}{1}\)
\(=\dfrac{\sqrt{x}+1+\sqrt{x}-1}{x-1}\cdot\dfrac{\sqrt{x}+1}{1}\)
\(=\dfrac{2\sqrt{x}}{\sqrt{x}-1}\)
c: Để A=3 thì \(2\sqrt{x}=3\sqrt{x}-3\)
=>x=9
d: Để A là số nguyên thì \(2\sqrt{x}-2+2⋮\sqrt{x}-1\)
\(\Rightarrow\sqrt{x}-1\in\left\{1;-1;2;-2\right\}\)
hay \(x\in\left\{4;9\right\}\)