\(n_{Zn}=\dfrac{6.5}{65}=0.1\left(mol\right)\)
\(n_{HCl}=\dfrac{7.3}{36.5}=0.2\left(mol\right)\)
\(Zn+2HCl\rightarrow ZnCl_2+H_2\)
\(0.1.......0.2...........0.1..........0.1\)
\(m_{ZnCl_2}=0.1\cdot136=13.6\left(g\right)\)
\(m_{H_2}=0.1\cdot2=0.2\left(g\right)\)