\(2Fe+3Cl_2\rightarrow2FeCl_3\)
0,2......0,3..........0,2.....
\(\Rightarrow A=m_{Fe}=11,2g\)
\(\Rightarrow B=m_{FeCl3}=32,5g\)
\(FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3+3NaCl\)
.0,2...........0,6...............0,2........
\(\Rightarrow C=m_{ddNaOH}=480g\)
\(2Fe\left(OH\right)_3\rightarrow Fe_2O_3+3H_2O\)
...0,2..................0,1...........
\(\Rightarrow E=m_{Fe2O3}=16g\)