Áp dụng t/c dtsbn:
\(\dfrac{a}{b}=\dfrac{c}{d}\Rightarrow\dfrac{a}{c}=\dfrac{b}{d}=\dfrac{3a}{3c}=\dfrac{4b}{4d}=\dfrac{3a+4b}{3c+4d}\left(1\right)\)
\(\dfrac{a}{c}=\dfrac{b}{d}=\dfrac{6a}{6c}=\dfrac{7b}{7d}=\dfrac{6a+7b}{6c+7d}\left(2\right)\)
\(\left(1\right)\left(2\right)\RightarrowĐpcm\)