Ta có: \(n_{Al}=\dfrac{5,4}{27}=0,2\left(mol\right)\)
PT: \(2Al+6HCl\rightarrow2AlCl_3+3H_2\)
_____0,2_____0,6____________0,3 (mol)
a, \(m_{ddHCl}=\dfrac{0,6.36,5}{15\%}=146\left(g\right)\)
b, m dd A = 5,4 + 146 - 0,3.2 = 150,8 (g)
c, \(V_{H_2}=0,3.24,79=7,437\left(l\right)\)
d, \(2H_2+O_2\underrightarrow{t^o}2H_2O\)
___0,3____0,15 (mol)
\(\Rightarrow V_{O_2}=0,15.24,79=3,7185\left(l\right)\)
\(\Rightarrow V_{kk}=5V_{O_2}=18,5925\left(l\right)\)