Ta có: \(n_{SO_2}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\)
PT: \(SO_2+Ca\left(OH\right)_2\rightarrow CaSO_3+H_2O\)
____0,15____0,15_______0,15 (mol)
a, \(C_{M_{Ca\left(OH\right)_2}}=\dfrac{0,15}{0,2}=0,75\left(M\right)\)
b, \(m_{CaSO_3}=0,15.120=18\left(g\right)\)