a, \(CuO+2HCl\rightarrow CuCl_2+H_2O\)
b, \(n_{CuO}=\dfrac{32}{80}=0,4\left(mol\right)\)
Theo PT: \(n_{HCl}=2n_{CuO}=0,8\left(mol\right)\Rightarrow C_{M_{HCl}}=\dfrac{0,8}{0,1}=8\left(M\right)\)
c, \(n_{H_2}=n_{CuO}=0,4\left(mol\right)\Rightarrow V_{H_2}=0,4.22,4=8,96\left(l\right)\)