a, \(CH_3COOH+C_2H_5OH⇌CH_3COOC_2H_5+H_2O\) (đk: to, H2SO4 đặc)
b, \(n_{CH_3COOH}=\dfrac{30}{60}=0,5\left(mol\right)\)
Theo PT: \(n_{C_2H_5OH}=n_{CH_3COOC_2H_5}=n_{CH_3COOH}=0,5\left(mol\right)\)
\(\Rightarrow m_{CH_3COOC_2H_5}=0,5.88=44\left(g\right)\)
c, \(C_{M_{C_2H_5OH}}=\dfrac{0,5}{0,05}=10\left(M\right)\)