`a)PTHH:`
`Zn + 2HCl -> ZnCl_2 + H_2 \uparrow`
`0,4` `0,8` `0,4` `0,4` `(mol)`
`n_[Zn]=26/65=0,4(mol)`
`b)m_[ZnCl_2]=0,4.136=54,4(g)`
`V_[H_2]=0,4.22,4=8,96(l)`
`c)m_[dd HCl]=[0,8.36,5]/10 . 100=292(g)`
`=>C%_[ZnCl_2]=[54,4]/[26+292-0,4.2] . 100~~17,15%`