\(\left(3x^2-2x+3\right):\left(x^2+1\right)\\ =\left[3\left(x^2+1\right)-2x\right]:\left(x^2+1\right)\\ =3\left(\text{dư }-2x\right)\\ \left(3x^2-4x+4\right):\left(x^2+2\right)\\ =\left(3x^2+6-4x-2\right):\left(x^2+2\right)\\ =\left[3\left(x^2+2\right)-4x-2\right]:\left(x^2+2\right)\\ =3\left(\text{dư }-4x-2\right)\)