Do \(u\) nhanh pha hơn \(i\) là \(\dfrac{\text{π }}{6}rad\) nên mạch gồm \(L\) và \(R\)
Có:
\(\tan \dfrac{\text{π }}{6}=\dfrac{Z_L}{R}\Rightarrow\dfrac{Z_L}{R}=\dfrac{\sqrt{3}}{3}\Rightarrow R=\sqrt{3}Z_L\)
\(Z=\dfrac{U}{I}=\dfrac{200}{2}=100\Rightarrow R^2+Z_L^2=100^2\)
\(\Rightarrow\left\{{}\begin{matrix}Z_L=50\Omega\Rightarrow L=\dfrac{1}{2\text{π }}\\R=50\sqrt{3}\Omega\end{matrix}\right.H\)