Question

Câu 8 ạ . Mik cần gấp

Answer 1

Câu 8 : 

s) $Fe + 2HCl \to FeCl_2 + H_2$

Theo PTHH :

$n_{H_2} = n_{Fe} = \dfrac{2,8}{56} = 0,05(mol)$

$V_{H_2} = 0,05.22,4 = 1,12(lít)$

b)

$n_{FeCl_2} = n_{Fe} = 0,05(mol)$

$\Rightarrow m_{FeCl_2} = 0,05.127 = 6,35(gam)$