\(n_{C_2H_4}=\dfrac{11.2}{22.4}=0.5\left(mol\right)\)
\(C_2H_4+3O_2\underrightarrow{^{t^0}}2CO_2+2H_2O\)
\(0.5.......1.5.............1\)
\(V_{O_2}=1.5\cdot22.4=33.6\left(l\right)\)
\(V_{CO_2}=1\cdot22.4=22.4\left(l\right)\)
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\(n_{C_2H_4}=\dfrac{11.2}{22.4}=0.5\left(mol\right)\\ C_2H_4+3O_2->2CO_2+2H_2O\\ =>n_{O_2}=3\cdot0.5=1.5\left(mol\right)\\ =>V_{O2}=1.5\cdot22.4=33.6\left(l\right)\\ n_{CO2}=2\cdot0.5=1\\ =>V_{CO2}=1\cdot22.4=22.4\left(l\right)\)
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