a: \(3\left(x-5\right)+\frac32\left(2x+1\right)=\frac53\)
=>\(3x-15+3x+\frac32=\frac53\)
=>\(6x=\frac53-\frac32+15=\frac{10}{6}-\frac96+15=15+\frac16=\frac{91}{6}\)
=>\(x=\frac{91}{6}:6=\frac{91}{36}\)
b: \(\left(x+2\right)^2-\left(x-2\right)\left(x+2\right)=0\)
=>(x+2)(x+2-x+2)=0
=>4(x+2)=0
=>x+2=0
=>x=-2