- Ta có: \(n_{NaOH\left(2M\right)}=0,5.2=1\left(mol\right)\)
Gọi VH2O thêm vào = a (ml)
\(\Rightarrow V_{NaOH\left(1M\right)}=\dfrac{1}{1}=1\left(l\right)=1000\left(ml\right)=500+a\)
\(\Rightarrow a=500\left(ml\right)\)
- PT: \(4P+5O_2\underrightarrow{t^o}2P_2O_5\) - pư hóa hợp.
\(Fe+2HCl\rightarrow FeCl_2+H_2\) - pư thế