\(n_{NaOH}=\dfrac{200.10\%}{40}=0,5\left(mol\right)\)
\(NaOH+HCl\rightarrow NaCl+H_2O\)
0,5 0,5 0,5 ( mol )
\(m_{dd_{HCl}}=\dfrac{0,5.46,5}{3,65\%}=500\left(g\right)\)
\(m_{ddspứ}=200+500=700\left(g\right)\)
\(C\%_{NaCl}=\dfrac{0,5.58,5}{700}.100=4,17\%\)