Question

Các bn làm nhanh nhé m cảm ơn <3

Answer 1

=>(3x-1)⁴+(3x-1)=0

=>(3x-1)[(3x-1)³+1]=0

=>3x-1=0 hoặc 3x-1=-1

=>x=1/3 hoặc x=0

Answer 2

Có: \(1-3x=\left(3x-1\right)^4\)

\(\Rightarrow1-3x=\left(1-3x\right)^4\)

\(\Rightarrow1-3x\left[1-\left(1-3x\right)^3\right]=0\)

\(\Rightarrow\left[{}\begin{matrix}1-3x=0\\1-\left(1-3x\right)^3=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=0\end{matrix}\right.\)

Answer 3

=>(3x-1)⁴+(3x-1)=0

=>(3x-1)[(3x-1)³+1]=0

=>3x-1=0 hoặc 3x-1=-1

=>x=1/3 hoặc x=0