(2x-2)2 = 16
(2x-2) = 4 vì 4 x 4 = 16
2x = 4 + 2
2x = 6
x = 6 : 2
x = 3
(2x - 2)2 = 16
=> (2x - 2)2 = 42 = (-4)2
=> \(2x-2\in\left\{4;-4\right\}\)
=> \(2x\in\left\{6;-2\right\}\)
=> \(x\in\left\{3;-1\right\}\)
Vậy \(x\in\left\{3;-1\right\}\)
\(\left(2x-2\right)^2=16\)
\(\Leftrightarrow\orbr{\begin{cases}2x-2=4\\2x-2=-4\end{cases}}\Leftrightarrow\orbr{\begin{cases}2x=6\\2x=-2\end{cases}\Leftrightarrow\orbr{\begin{cases}x=3\\x=-1\end{cases}}}\)