Question

C=7-\(\left(-\dfrac{4}{5}\right)^{0+}\left(\dfrac{1}{3}\right)^2:2\)

Answer 1

\(C=7-\left(-\dfrac{4}{5}\right)^0+\left(\dfrac{1}{3}\right)^2:2\\ =7-1+\dfrac{1}{9}.\dfrac{1}{2}\\ =6+\dfrac{1}{18}=\dfrac{109}{18}\)

Answer 2

\(C=7-\left(-\dfrac{4}{5}\right)^0+\left(\dfrac{1}{3}\right)^2:2\)

\(=7-1+\dfrac{1}{9}:2\)

\(=6+\dfrac{1}{18}=\dfrac{108}{18}+\dfrac{1}{18}=\dfrac{109}{18}\)

Answer 3

\(C=7-\left(-\dfrac{4}{5}\right)^0+\left(\dfrac{1}{3}\right)^2:2\)

\(C=7-1+\dfrac{1}{9}:2\)

\(C=6+\dfrac{1}{9}.\dfrac{1}{2}\)

\(C=6+\dfrac{1}{18}\)

\(C=\dfrac{109}{18}\)