\(\left(105-x\right)\div2^5=3^0+1\)
\(\left(105-x\right)\div2^5=2\)
\(\left(105-x\right)=2\times2^5\)
\(105-x=2^6\)
\(x=105-64\)
x=41
c) (105 - x):32 = 2
105 - x = 2.32
105 - x = 64
x = 105 - 64
Vậy x = 41.
\(\left(105-x\right):2^5=0+1\)
\(105-x=1.2^5\)
\(x=105-32\)
\(x=73\)