\(n_C=\dfrac{m}{M}=\dfrac{12}{12}=1\left(mol\right)\\ PTHH:C+O_2-^{t^o}>CO_2\)
tỉ lệ 1 : 1 : 1
n(mol) 1---->1----------->1
\(m_{O_2}=n\cdot M=1\cdot32=32\left(g\right)\\ V_{CO_2\left(dktc\right)}=n\cdot22,4=1\cdot22,4=22,4\left(l\right)\)
Ta có: \(n_C=\dfrac{12}{12}=1\left(mol\right)\)
PT: \(C+O_2\underrightarrow{t^o}CO_2\)
____1____1____1 (mol)
a, \(m_{O_2}=1.32=32\left(g\right)\)
b, \(V_{CO_2}=1.22,4=22,4\left(l\right)\)