d) \(\dfrac{2}{19}.\dfrac{-4}{7}+\dfrac{2}{19}.\dfrac{-3}{7}\)
= \(\dfrac{2}{19}.\left(\dfrac{-4}{7}+\dfrac{-3}{7}\right)\)
=\(\dfrac{2}{19}.\left(-1\right)=\dfrac{-2}{19}\)
Giải:
2/19.-4/7+2/19.-3/7
=2/19.(-4/7+-3/7)
=2/19.-1
=-2/19
Chúc bạn học tốt!
a) Ta có: \(-\dfrac{2}{13}+\dfrac{-4}{7}-\dfrac{3}{7}+\dfrac{15}{13}\)
\(=\dfrac{-2+15}{13}+\dfrac{-4-3}{7}\)
\(=\dfrac{13}{13}+\dfrac{-7}{7}\)
=1-1=0