Ta có:
\(x^2-4x+5+y^2+2y=0\)
\(\Leftrightarrow\left(x^2-2.2x+2^2\right)+\left(y^2+2y+1^2\right)=0\)
\(\Leftrightarrow\left(x-2\right)^2+\left(y+1\right)^2=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\y+1=0\end{matrix}\right.\) (Vì: (x-2)^2+ (y+1)^2 lớn hơn hoặc bằng - vs mọi x
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\y=-1\end{matrix}\right.\)