Question

bài 2 : so sánh

a, \(9^{20}\) và \(27^{13}\)

Answer 1

\(9^{20}\) và \(27^{13}\)

Có: \(27^{13}=\left(3^3\right)^{13}=3^{39}\)

\(9^{20}=\left(3^2\right)^{20}=3^{40}\)

⇒ \(9^{20}>27^{13}\)

Answer 2

`9^20 = 3^2^(20) = 3^(2.20) = 3^40`.

`27^13 = 3^3^(13) = 3^(3.13) = 3^39`

Vậy `9^20 > 27^13`

Answer 3

9^20 > 27^13