`a)[3x+2]/2-[3x+1]/6=5/3+2x`
`<=>3(3x+2)-(3x+1)=10+6.2x`
`<=>9x+6-3x-1=10+12x`
`<=>-6x=5`
`<=>x=[-5]/6` Vậy `S={[-5]/6}`
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`b)[4x+3]/5-[6x-2]/7=[5x+4]/3+3`
`<=>21(4x+3)-15(6x-2)=35(5x+4)+315`
`<=>84x+63-90x+30=175x+140+315`
`<=>-181x=362`
`<=>x=-2` Vậy `S={-2}`
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`c)[x+4]/5-x+4=x/3-[x-2]/2`
`<=>6(x+4)-30(x-4)=10x-15(x-2)`
`<=>6x+24-30x+120=10x-15x+30`
`<=>-19x=-114`
`<=>x=6` Vậy `S={6}`
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`d)[5x+2]/6-[8x-1]/3=[4x+2]/5-5`
`<=>5(5x+2)-10(8x-1)=6(4x+2)-150`
`<=>25x+10-80x+10=24x+12-150`
`<=>-79x=-158`
`<=>x =2` Vậy `S={2}`
2a. \(\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=\dfrac{5}{3}+2x\)
\(\Leftrightarrow3\left(3x+2\right)-\left(3x+1\right)=10+12x\)
\(\Leftrightarrow9x+6-3x-1=10+12x\)
\(\Leftrightarrow-6x=5\Leftrightarrow x=-\dfrac{5}{6}\)
Vậy : Phương trình có tập nghiệm \(S=\left\{-\dfrac{5}{6}\right\}\)
b. \(\dfrac{4x+3}{5}-\dfrac{6x-2}{7}=\dfrac{5x+4}{3}+3\)
\(\Leftrightarrow21\left(4x+3\right)-15\left(6x-2\right)=35\left(5x+13\right)\)
\(\Leftrightarrow84x+63-90x+30=175x+455\)
\(\Leftrightarrow-181x=362\Leftrightarrow x=-2\)
Vậy : Phương trình có tập nghiệm \(S=\left\{-2\right\}\)
c. \(\dfrac{x+4}{5}-x+5=\dfrac{x}{3}-\dfrac{x-2}{2}\)
\(\Leftrightarrow6\left(x+4\right)-30x+150=10x-15\left(x-2\right)\)
\(\Leftrightarrow6x+24-30x+150=10x-15x+30\)
\(\Leftrightarrow-19x=-144\Leftrightarrow x=\dfrac{144}{19}\)
Vậy : Phương trình có tập nghiệm \(S=\left\{\dfrac{144}{19}\right\}\)
d. \(\dfrac{5x+2}{6}-\dfrac{8x-1}{3}=\dfrac{4x+2}{5}-5\)
\(\Leftrightarrow5\left(5x+2\right)-10\left(8x-1\right)=6\left(4x+2\right)-150\)
\(\Leftrightarrow25x+10-80x+10=24x+12-150\)
\(\Leftrightarrow-79x=-158\Leftrightarrow x=2\)
Vậy : Phương trình có tập nghiệm \(S=\left\{2\right\}\)
