Question

Bài 2. (1 điểm) Phân tích các đa thức sau thành nhân tử:

a) $10{{x}^{2}}\left( 2x-y \right)+6xy\left( y-2x \right);$

b) ${{x}^{2}}-2x+1-{{y}^{2}}$.

Answer 1

`a, 10x^2 (2x-y) +6xy(y-2x)`

`= 10x^2 (2x-y) -6xy(2x-y)`

`= (2x-y)(10x^2 -6xy)`

`= 2x(2x-y)(5x- 3y)`

`b, x^2 -2x+1-y^2`

`=(x^2-2x+1)-y^2`

`=(x-1)^2-y^2`

`=(x-1-y)(x-1+y)`

Answer 2

a) \(10x^2\left(2x-y\right)+6xy\left(y-2x\right)\)

\(=10x^2\left(2x-y\right)-6xy\left(2x-y\right)\)

\(=\left(2x-y\right)\left(10x^2-6xy\right)\)

\(=2x\left(2x-y\right)\left(5x-3y\right)\)

b) \(x^2-2x+1-y^2\)

\(=\left(x-1\right)^2-y^2\)

\(=\left(x-y-1\right)\left(x+y-1\right)\)