a: \(=x^2-6x+9+2=\left(x-3\right)^2+2>=2\)
Dấu = xảy ra khi x=3
b: \(=3\left(x^2-\dfrac{5}{3}x+\dfrac{7}{3}\right)\)
\(=3\left(x^2-2\cdot x\cdot\dfrac{5}{6}+\dfrac{25}{36}+\dfrac{59}{36}\right)\)
\(=3\left(x-\dfrac{5}{6}\right)^2+\dfrac{59}{12}>=\dfrac{59}{12}\)
Dấu = xảy ra khi x=5/6
d: \(=x^2+2x-3+11=x^2+2x+8=\left(x+1\right)^2+7>=7\)
Dấu = xảy ra khi x=-1