Bài 2:
( 3x - 1 ) ^ 2 - 16 = 0
=> (3x-1)^2=16
=>3x-1)^2=4^2
=>3x-1=4
=>3x=5 =>x=5/3
Bài3:
b, xy-x^2-x+y
= (xy-x^2) - (x-y)
= x(y-x)+(y-x)
=(y-x)(x+1)
Bai 3:
a: \(=3\left(x^2-10x+25\right)=3\left(x-5\right)^2\)
b: \(=x\left(y-x\right)+\left(y-x\right)=\left(y-x\right)\left(x+1\right)\)
c: \(=\left(x-8\right)\left(x+1\right)\)