Question

Bài 1. (3,0 điểm) Cho biểu thức P= (2+𝑥2−𝑥 - 𝑥2𝑥2−4 - 2− 𝑥2+𝑥 ): 𝑥2−3𝑥2𝑥2−𝑥3

a) Rút gọn P

Answer 1

\(P=\left(\dfrac{2+x}{2-x}-\dfrac{x^2+4}{x^2-4}-\dfrac{2-x}{2+x}\right):\dfrac{x^2-3x}{2x^2-x^3}\)

\(=\left(\dfrac{-\left(x+2\right)}{x-2}-\dfrac{x^2+4}{\left(x-2\right)\left(x+2\right)}+\dfrac{x-2}{x+2}\right)\cdot\dfrac{x^2\left(2-x\right)}{x\left(x-3\right)}\)

\(=\dfrac{-x^2-4x-4-x^2-4+x^2-4x+4}{\left(x-2\right)\left(x+2\right)}\cdot\dfrac{-x\left(x-2\right)}{x-3}\)

\(=\dfrac{-x^2-8x-4}{\left(x+2\right)}\cdot\dfrac{-x}{x-3}=\dfrac{x\left(x^2+8x+4\right)}{\left(x+2\right)\left(x-3\right)}\)