Question

B1 : thực hiện phép tính

i)  \(\left(\dfrac{10}{3}+\dfrac{5}{2}\right)\):\(-\dfrac{11}{31}\)

p) (-2)³ . \(\dfrac{1}{24}\)+ (\(\dfrac{4}{3}\)-1\(\dfrac{5}{6}\)) : \(\dfrac{5}{12}\)

 _{giúp nhanh ạ, mình cần gấp}

 

Answer 1

\(i.\left(\dfrac{10}{3}+\dfrac{5}{2}\right):\dfrac{-11}{31}\\ =\left(\dfrac{20}{6}+\dfrac{15}{6}\right)\cdot\dfrac{-31}{11}\\ =\dfrac{35}{6}\cdot\dfrac{-31}{11}\\ =\dfrac{-1085}{66}\\ p.\left(-2\right)^3\cdot\dfrac{1}{24}+\left(\dfrac{4}{3}-1\dfrac{5}{6}\right):\dfrac{5}{12}\\ =\left(-8\right)\cdot\dfrac{1}{24}+\left(\dfrac{4}{3}-\dfrac{11}{6}\right):\dfrac{5}{12}\\ =-\dfrac{1}{3}+-\dfrac{1}{2}\cdot\dfrac{12}{5}\\ =\dfrac{-1}{3}+\dfrac{-6}{5}\\ =\dfrac{-23}{15}\)