Question

b) x(y + 1) - (y + 1)= 10

Answer 1

=>(y+1)(x-1)=10

\(\Leftrightarrow\left(x-1,y+1\right)\in\left\{\left(1;10\right);\left(2;5\right);\left(10;1\right);\left(5;2\right);\left(-1;-10\right);\left(-2;-5\right);\left(-10;-1\right);\left(-5;-2\right)\right\}\)

hay \(\left(x,y\right)\in\left\{\left(2;9\right);\left(3;4\right);\left(11;0\right);\left(6;1\right);\left(0;-11\right);\left(-1;-6\right);\left(-9;-2\right);\left(-9;-2\right);\left(-4;-3\right)\right\}\)

Answer 2