a)\(\dfrac{x}{60}=-\dfrac{3}{4}\)
\(\Rightarrow x\cdot4=60\cdot\left(-3\right)\)
\(x\cdot4=-180\)
x=45
b)\(\dfrac{2}{5}=\dfrac{12}{x}\)
\(\Rightarrow2x=5\cdot12\)
\(2x=60\)
x=30
c)\(x-\dfrac{5}{7}=\dfrac{6}{21}\)
\(x=\dfrac{2}{7}+\dfrac{5}{7}\)
x=1
d)\(x+\dfrac{7}{8}=\dfrac{63}{24}\)
\(x=\dfrac{21}{8}-\dfrac{7}{8}\)
\(\dfrac{14}{8}\)
a)\(\dfrac{x}{60}=\dfrac{-3}{4}\Rightarrow x=\dfrac{-3.60}{4}=-45\)
b)\(\dfrac{2}{5}=\dfrac{12}{x}\Rightarrow x=\dfrac{5.12}{2}=30\)
c)\(\dfrac{x-5}{7}=\dfrac{6}{21}\Rightarrow x-5=\dfrac{6.7}{21}=2\Rightarrow x=2+5=7\)
d)\(\dfrac{x+7}{8}=\dfrac{63}{24}\Rightarrow x+7=\dfrac{8.63}{24}=21\\ \Rightarrow x=21-7=14\)
a: \(\dfrac{x}{60}=-\dfrac{3}{4}\)
nên x=-45
b: \(\dfrac{2}{5}=\dfrac{12}{x}\)
nên x=30
c: \(x-\dfrac{5}{7}=\dfrac{6}{21}\)
nên x=1
d: Ta có: \(x+\dfrac{7}{8}=\dfrac{63}{24}\)
nên x=2